1/6x^2+1/x=1/2x^2

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Solution for 1/6x^2+1/x=1/2x^2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/6)*x^2+1/x = (1/2)*x^2 // - (1/2)*x^2

(1/6)*x^2-((1/2)*x^2)+1/x = 0

(1/6)*x^2+(-1/2)*x^2+1/x = 0

x^-1-1/3*x^2 = 0

x^-1*(1-1/3*x^3) = 0

-1/3*x^3 = -1 // : -1/3

x^3 = 3

x^3 = 3 // ^ 1/3

x = 3^(1/3)

1/x = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = 3^(1/3)

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